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Multi-Electron Configurations and Orbital Diagrams

Question

Which of the following electronic configuration is impossible ?

A

1 s^{2}, 2 s^{2}, 2 p^{6}

B

1 s^{2}, 2 s^{2}, 2 p^{7}

C

1 s^{2}, 2 s^{2}

D

1 s^{2}, 2 s^{2}, 2 p^{5}

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Solution

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p subshell with 3 orbitals can accomodate 6 electrons only. The seventh electron cannot enter. Therefore ${1 s}^{2} {2 s}^{2} {2 p}^{7}$ is not possible.

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