Which of the following electronic configuration is impossible ?
1s2,2s2,2p6
1s2,2s2,2p7
1s2,2s2
1s2,2s2,2p5
A
1s2,2s2
B
1s2,2s2,2p7
C
1s2,2s2,2p6
D
1s2,2s2,2p5
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Solution
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p subshell with 3 orbitals can accomodate 6 electrons only. The seventh electron cannot enter. Therefore 1s22s22p7 is not possible.
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