Find the total number of compounds containing X - O - X linkage. (Where X is the central atom)
(1) $H_{2} S_{4} O_{6}$
(2) $H_{6} P_{6} O_{18}$
(3) $P_{4} O_{10}$
(4) $N a_{2} B_{4} O_{5} (O H)_{4} .8 H_{2} O$
(5) $N a_{2} S_{2} O_{8}$
(6) $K_{2} S_{2} O_{7}$
(7) $K_{2} C r_{2} O_{7}$
(8) $N a_{4} P_{2} O_{8}$
(9) $H_{4} P_{2} O_{6}$

Question

Find the total number of compounds containing X - O - X linkage. (Where X is the central atom)

(1)

H_{2} S_{4} O_{6}

(2)

H_{6} P_{6} O_{18}

(3)

P_{4} O_{10}

(4)

N a_{2} B_{4} O_{5} (O H)_{4} .8 H_{2} O

(5)

N a_{2} S_{2} O_{8}

(6)

K_{2} S_{2} O_{7}

(7)

K_{2} C r_{2} O_{7}

(8)

N a_{4} P_{2} O_{8}

(9)

H_{4} P_{2} O_{6}

Toppr Admin · Accepted Answer

H6P6O18-P4O10-Na2B4O5-OH-4-8H2O-K2S2O7-K2Cr2O7 has X-O-X linkage-

Find the total number of compounds containing X - O - X linkage. (Where X is the central atom)(1) H2S4O6(2) H6P6O18 (3) P4O10(4) Na2B4O5(OH)4.8H2O(5) Na2S2O8(6) K2S2O7(7) K2Cr2O7(8) Na4P2O8(9) H4P2O65978