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Question

which of the following is an even function
  1. ax+axaxax
  2. f(x)=xax1ax+1
  3. f(x)=log2(x+x2+1)
  4. f(x)=ax+1ax1

A
f(x)=ax+1ax1
B
f(x)=log2(x+x2+1)
C
f(x)=xax1ax+1
D
ax+axaxax
Solution
Verified by Toppr

Consider the given expression,

x(ax1)(ax+1)

Replace x by –x , we get,

=x(ax1)(a(x)+1)$

=x(1ax1)(1ax+1)=x(1axax)(1+axax)

=x(1ax)1+ax=x((1+ax))1+ax

=x(ax1)1+ax


=x(ax1)(ax+1) is the even function.

Option (c) is correct answer

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