Which of the following is soluble- Bi - 2 - S - 3 -left- - K - sp -1times - 10 - -70 - right- CuSleft- - K - sp -8times - 10 - -37 - right- - Ag - 2 -Sleft- - K - sp -6times - 10 - -51 - right- MnSleft- - K - sp -7times - 10 - -16 - right-

Question

Toppr Admin · Accepted Answer

Solubility of an electrolyte increases with increase in their ionic product i-e- solubility product- Now-xA0-Ksp-MnS-gt-Ksp-CuS-gt-Ksp-Ag2S-gt-Ksp-Bi2S3-Therefore MnS will be most soluble-

Marks	1 - 10	11 - 20	21 30	31 - 40	41 -50	51 - 60	61 - 70
No. of student	6	5	8	15	7	6	3

Which of the following is most soluble?
${B i}_{2} S_{3} (K_{s p} = 1 \times 10^{- 70})$
$C u S (K_{s p} = 8 \times 10^{- 37})$
${A g}_{2} S (K_{s p} = 6 \times 10^{- 51})$
$M n S (K_{s p} = 7 \times 10^{- 16})$

Solubility of an electrolyte increases with increase in their ionic product i.e. solubility product. Now,
$K_{s p} (M n S) > K_{s p} (C u S) > K_{s p} ({A g}_{2} S) > K_{s p} ({B i}_{2} S_{3})$
Therefore $M n S$ will be most soluble.

Which of the following is most soluble?Bi2S3(Ksp=1×10−70)CuS(Ksp=8×10−37)Ag2S(Ksp=6×10−51)MnS(Ksp=7×10−16)

Solubility of an electrolyte increases with increase in their ionic product i.e. solubility product. Now, Ksp(MnS)>Ksp(CuS)>Ksp(Ag2S)>Ksp(Bi2S3)Therefore MnS will be most soluble.

Which of the following is most soluble?
${B i}_{2} S_{3} (K_{s p} = 1 \times 10^{- 70})$
$C u S (K_{s p} = 8 \times 10^{- 37})$
${A g}_{2} S (K_{s p} = 6 \times 10^{- 51})$
$M n S (K_{s p} = 7 \times 10^{- 16})$

Solubility of an electrolyte increases with increase in their ionic product i.e. solubility product. Now,
$K_{s p} (M n S) > K_{s p} (C u S) > K_{s p} ({A g}_{2} S) > K_{s p} ({B i}_{2} S_{3})$
Therefore $M n S$ will be most soluble.