Which of the following relationships is correct for a reaction involving both reactants and products both in either solid or liquid state?
$△ H = △ E$
$△ H < △ E$
$△ H > △ E$
$△ H - △ E = \infty$

Question

Which of the following relationships is correct for a reaction involving both reactants and products both in either solid or liquid state?
$△ H = △ E$
$△ H < △ E$
$△ H > △ E$
$△ H - △ E = \infty$

Toppr Admin · Accepted Answer

If the-xA0- reaction involves products and reactants in solid-liquid in state then-x25B3-ng-0-x25B3-H-x25B3-E-x25B3-n-gRT-x25B3-H-x25B3-ESo- B is the correct answer-

Which of the following relationships is correct for a reaction involving both reactants and products both in either solid or liquid state?△H=△E△H<△E△H>△E△H−△E=∞

If the reaction involves products and reactants in solid/liquid in state then,△ng=0△H=△E+(△n)gRT△H=△ESo, B is the correct answer.

Which of the following relationships is correct for a reaction involving both reactants and products both in either solid or liquid state?
$△ H = △ E$
$△ H < △ E$
$△ H > △ E$
$△ H - △ E = \infty$

If the reaction involves products and reactants in solid/liquid in state then, $△ n_{g} = 0$
$△ H = △ E + (△ n)_{g} R T$
$△ H = △ E$
So, B is the correct answer.