Which of the following sets of quanta numbers could represent the last electron added to complete the electronic configuration for a ground state atom of Br (Z = 35)?
$4, 0, 0, - \frac{1}{2}$
$4, 1, 1, - \frac{1}{2}$
$3, 1, 1, - \frac{1}{2}$
$4, 1, 2, + \frac{1}{2}$

Question

Which of the following sets of quanta numbers could represent the last electron added to complete the electronic configuration for a ground state atom of Br (Z = 35)?
$4, 0, 0, - \frac{1}{2}$
$4, 1, 1, - \frac{1}{2}$
$3, 1, 1, - \frac{1}{2}$
$4, 1, 2, + \frac{1}{2}$

Toppr Admin · Accepted Answer

The valence node shell configuration is 4s24p5 for the last electron n-4-l-1-m-x2212-1-0 or -1-s-12 or -x2212-12-Hence- 4-1-1-x2212-12Therefore- option B is correct-

Which of the following sets of quanta numbers could represent the last electron added to complete the electronic configuration for a ground state atom of Br (Z = 35)? 4,0,0,−124,1,1,−123,1,1,−124,1,2,+12

The valence node shell configuration is 4s24p5 for the last electron n=4,l=1.m=−1,0 or +1,s=+12 or −12.Hence, 4,1,1,−12Therefore, option B is correct.

Which of the following sets of quanta numbers could represent the last electron added to complete the electronic configuration for a ground state atom of Br (Z = 35)?
$4, 0, 0, - \frac{1}{2}$
$4, 1, 1, - \frac{1}{2}$
$3, 1, 1, - \frac{1}{2}$
$4, 1, 2, + \frac{1}{2}$

The valence node shell configuration is $4 s^{2} 4 p^{5}$ for the last electron $n = 4, l = 1$ .

$m = - 1, 0$ or $+ 1, s = + \frac{1}{2}$ or $- \frac{1}{2}$ .

Hence, $4, 1, 1, - \frac{1}{2}$

Therefore, option B is correct.