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Standard IX
Chemistry
Quantum Number
Question

Which of the following sets of quantum numbers is correct for an electron in 4f orbital?
  1. n = 4, l = 3, m = +4, s = +1/2
  2. n = 4, l = 4, m = -4, s = -1/2
  3. n = 4, l = 3, m = +1, s = +1/2
  4. n = 3, l = 2, m = -2, s = +1/2

A
n = 4, l = 3, m = +1, s = +1/2
B
n = 3, l = 2, m = -2, s = +1/2
C
n = 4, l = 3, m = +4, s = +1/2
D
n = 4, l = 4, m = -4, s = -1/2
Open in App
Solution
Verified by Toppr

For 4f orbitals : n=4,l=3,m=−3to3, s=±1/2

So, C is the correct option.

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Similar Questions
Q1
Which of the following sets of quantum numbers is correct for an electron in 4f− orbital?
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Q2

Which of the following sets of quantum numbers is correct for an electron in 4f orbital?


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Q3
The decreasing order of energy for the electron represented by the following sets of quantum number is
(1) n=4,l=0,m=0,s=+12
(2) n=3,l=2,m=+1,s=−12
(3) n=3,l=2,m=−1,s=+12
(4) n=3,l=1,m=0,s=+12
(5) n=5,l=2,m=+1,s=−12
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Q4
Consider the following sets of quantum numbers.
(i) n - 3, l - 0, m - 0, s - +1/2

(ii) n - 2, l - 2, m - 1, s - +1/2
(iii) n - 4, l - 3, m - 2, s -1/2
(iv) n - 1, l - 0, m - 1, s -1/2
(v) n - 3, l - 2, m - 3, s - +1/2
Which of the following sets of quantum numbers is not possible?

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Q5
The quantum numbers of six electrons are given below. Arrange them in order of increasing energies.
1. n=4,l=2,m1=−2,ms=−1/2
2. n=3,l=2,m1=1,ms=+1/2
3. n=4,l=1,m1=0,ms=+1/2
4. n=3,l=2,m1=−2,ms=−1/2
5. n=3,l=1,m1=−1,ms=+1/2
6. n=4,l=1,m1=0,ms=+1/2
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