Question

Which of the following statement is/are correct?

• A. $B_2{H}_6$ is not an electron-deficient compound
• B. $B{F}_3$ and $Br{F}_3$ molecules have different shapes
• C. Boron has an extremely high melting point because of the strong binding forces in the covalent polymer
• D. Ortho boric acid contains pyramidal $B{O}_3^{-3}$ units

Answer 1

Answer: (B), (C)

A) $B_2{H}_6$, diborane is an electron deficient compound.

B) Boron has a very strong crystalline lattice. So, it has an extremely high melting point.

C) $Br{F}_3$ has a bent structure whereas $B{F}_3$ has a trigonal planar structure. $B{F}_3$ has coplanar geometry due to $s{p}^2$ hybridisation on boron atom whereas $Br{F}_3$ has $s{p}^{3}d$ hybridisation and possesses two lone pairs of electron on Br atom which leads to T shaped geometry.

D) Ortho boric acid contains triangular $B{O}_3^{-3}$ units.

Option B and C are correct.