Which of the following statements is/are incorrect ?
This question has multiple correct options
In B2H6(s) there are four 2c−2e− bonds
In (SiH3)3P¨ there is back bonding
(CH3)3N¨ and (SiH3)3N¨ are pyramidal
Al2Cl6(s) has banana bonding
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Correct options are B) and C)
Only statement A is correct. All terminal B−H bonds are 2c-2e bonds. In (SiH3)3N, Si has vacant d-orbital which forms pπ−dπ bonding. So there is no back bonding in (SiH3)3N. (CH3)3N has sp3 hybridization on nitrogen with pyramidal shape due to pπ−pπ bonding whereas in (SiH3)3N, Si has vacant d orbitals which forms pπ−dπ bonding. So, (SiH3)3N has planar structure whereas (CH3)3N has pyramidal structure. Al2Cl6 is a dimer of AlCl3 in which Cl forms coordinate bond with Al as shown in figure.