The bleaching action of chlorine is due to oxidation and so permanent, while the bleaching action of sulphurdioxide is due to reduction and so temporary.
HI cannot be prepared by heating an ionic iodide with conc. H2SO4, but HCl can be prepared by the same way.
The oxidising power of halogens follow the order : Cl2>F2>Br2>I2.
On reaction of XeF2 with water, no redox change takes place.
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Correct options are A) and B)
It is permanent because here Chlorine gives bleach via oxidation atmosphere is also oxidizing. so it cannot be reversed.
Bleaching action of SO2 is due to reduction.
In this, SO2 reacts with water to form Sulphuric acid and nascent Hydrogen.
This nascent hydrogen reacts with Colour to give Colourless Product.
In this oxygen ie removed due to nascent hydrogen which makes the compound so colourless.
Since the atmosphere is oxidizing, the oxygen from the atmosphere takes place of there removed oxygen and slowly regains colour
hence it is temporary.
Hence A is correct.
-H2SO4 is an oxidising agent, when ionic iodide reacts with Conc H2SO4, It will cause I to oxidise into I2 instead of forming HI.This is because HI is a strong reducing agent and it will reduce H2SO4 to SO2
Whereas HCl can be prepared in the same way because it is slightly less acidic than H2SO4.