Which one of the following gives Prussion blue colour-displaystyle - Na - 4 -left- - Feleft- CN right- - 6 - right- displaystyle - - Fe - 3 -left- - Feleft- CN right- - 6 - right- - 3 -displaystyle - Fe - 2 -left- - Feleft- CN right- - 6 - right- displaystyle - - Fe - 4 -left- - Feleft- CN right- - 6 - right- - 3 -

Question

Toppr Admin · Accepted Answer

Prussian blue is described as a deep blue pigment that is produced when the oxidation of ferrous ferrocyanide salts occurs.

It contains ferric hexacyanoferrate(II) ${{F e}_{4} [{F e (C N)}_{6}]}_{3}$ in a cubic lattice crystal structure.

$4 F e C l_{3} + 3 K_{4} [F e (C N)_{6}] \to {{F e}_{4} [{F e (C N)}_{6}]}_{3} + 12 K C l$

So, the correct option is $D$ .

Which one of the following gives Prussion blue colour?Na4[Fe(CN)6]Fe3[Fe(CN)6]3Fe2[Fe(CN)6]Fe4[Fe(CN)6]3

Prussian blue is described as a deep blue pigment that is produced when the oxidation of ferrous ferrocyanide salts occurs. It contains ferric hexacyanoferrate(II) Fe4[Fe(CN)6]3 in a cubic lattice crystal structure. 4FeCl3+3K4[Fe(CN)6]→Fe4[Fe(CN)6]3+12KClSo, the correct option is D.

Which one of the following gives Prussion blue colour?
${N a}_{4} [{F e (C N)}_{6}]$
${{F e}_{3} [{F e (C N)}_{6}]}_{3}$
${F e}_{2} [{F e (C N)}_{6}]$
${{F e}_{4} [{F e (C N)}_{6}]}_{3}$