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Question

Which one of the following order is correct for the bond dissociation enthalpy of halogen molecules?
  1. Cl2>Br2>F2>I2
  2. I2>Br2>Cl2>F2
  3. Br2>I2>F2>Cl2
  4. F2>Cl2>Br2>I2

A
F2>Cl2>Br2>I2
B
I2>Br2>Cl2>F2
C
Br2>I2>F2>Cl2
D
Cl2>Br2>F2>I2
Solution
Verified by Toppr

Bond dissociation energy of halogen family decreases down the group as the size of atom increases.

The decreasing order for the bond dissociation enthalpy of halogen molecules is Cl2 57 kcal/mol>Br2 45.5 kcal/mol>F2 38 kcal/mol> 35.6 kcal/molI2.

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Similar Questions
Q1
Consider the following orders –
(1) F2>Cl2>Br2>I2: boiling point
(2) F2>Cl2>Br2>I2: oxidizing nature
(3) F2>Cl2>Br2>I2: EN
(4) F2>Cl2>Br2>I2: BDE
(5) F2>Cl2>Br2>I2: EA
(6) F2>Cl2>Br2>I2: Reactivity
(7) HOCl>HClO2>HClO3>HClO4: Acidic nature
(8) HOCl>HClO2>HClO3>HClO4: Oxidizing nature
Then calculate (x2+y2) when x is correct order and y is incorrect order.

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Q2
Arrange in increassing order of bond dissocation enthalpy of
F2,Cl2,Br2,I2
View Solution
Q3
Increasing oxidising nature of I2,Br2,Cl2,F2 is : I2<Br2<Cl2<F2.
if true enter 1, else enter 0.
View Solution
Q4
Write the Bond Energy order of :
F2, Cl2, Br2, I2
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Q5
Bond energy of different halogen molecules will lie in the sequence
Cl2>Br2>F2>I2

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