Which one of the following statements is correct when $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution?
The solution turns blue
The solution is decolourized
$S O_{2}$ is reduced
Green $C r_{2} (S O_{4})_{3}$ is formed

Question

Which one of the following statements is correct when $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution?
The solution turns blue
The solution is decolourized
$S O_{2}$ is reduced
Green $C r_{2} (S O_{4})_{3}$ is formed

Toppr Admin · Accepted Answer

When SO2 is passed through acidified K2Cr2O7 solution- green Cr2-SO4-3 is formed- -xA0-K2Cr2O7-3SO2-H2SO4-x2192-K2SO4-Cr2-SO4-3-H2OSulphur dioxide is oxidized to sulphuric acid- Potassium dichromate is reduced to chromic sulphate- Orange colour of solution turns green-

Which one of the following statements is correct when SO2 is passed through acidified K2Cr2O7 solution?The solution turns blueThe solution is decolourizedSO2 is reducedGreen Cr2(SO4)3 is formed

When SO2 is passed through acidified K2Cr2O7 solution, green Cr2(SO4)3 is formed. K2Cr2O7+3SO2+H2SO4→K2SO4+Cr2(SO4)3+H2OSulphur dioxide is oxidized to sulphuric acid. Potassium dichromate is reduced to chromic sulphate. Orange colour of solution turns green.

Which one of the following statements is correct when $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution?
The solution turns blue
The solution is decolourized
$S O_{2}$ is reduced
Green $C r_{2} (S O_{4})_{3}$ is formed