Which option correctly describes the equations for curves A and B, in the given graph of species-area relationship?
A - LogS=LogC+ZlogA; B - S=CAz
A - LogC=LogS+ZlogA; B - S=CAz
A - S=CAz; B - LogC=LogS+ZlogA
A - S=CAz; B - LogS=LogC+ZlogA
A
A - LogC=LogS+ZlogA; B - S=CAz
B
A - LogS=LogC+ZlogA; B - S=CAz
C
A - S=CAz; B - LogS=LogC+ZlogA
D
A - S=CAz; B - LogC=LogS+ZlogA
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Solution
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The correct option is A A - S=CAz; B - LogS=LogC+ZlogA
In the
given figure, the equation for curve A is S = CA^Z, and that for the curve B is
log S = log C + Zlog A.
So, the correct answer is 'A - S=CAz; B - LogS=LogC+ZlogA'.
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