Which sample, A or B shown in figure has shorter mean-life?
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Updated on : 2022-09-05
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Initially at t=0 from figure given (dtdN0)A=(dtdN0)B So (N0)A=(N0)B ie initially both samples has equal number of radioactive atoms. Considering at any instant t=t from figure. (dtdN0)A>(dtdN0)B λANA=λBNB NA>NB λA<λB(dt−dN=λN) ∴τ=λ1 ∴τA1<τB1 τA>τB So mean life time of sample A is greater than of B