Work function of metal surface is 1.6×10−19 joule when light of 6400 A wavelength incident on this surface then maximum kinetic energy of photo electron(in joule) is
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The minimum energy necessary to overcome the attractive force between the electron and the surface of silver metal is 7.52×10−19J. What will be the maximum kinetic energy of the electrons ejected from silver which is being irradiated with ultraviolet light having a wavelength 360Å?
Light of wavelength 300×10−9m strikes a metal a metal surface with photoelectric work function of 2.13eV. The kinetic energy of photoelectron is
The work function of a metal is 4.2 eV. If the radiation with wavelength 2000 0A falls on the metal surface then the kinetic energy of fastest photo electron will be:
If the work function for a certain metal is 3.2×10−19joule and it is illuminated with light of frequency 8×1014Hz. The maximum kinetic energy of the photo-electrons would be (h=6.63×10−34Js
The work function of a metal is 1.6×10−19J. When the metal surface is illuminated by the light of wavelength 6400∘A , then the maximum kinetic energy of emitted photo-electrons will be (Planck's constant h=6.4×10−34Js)