Work required to produce 1000 k - calorie heat will be4-2 Joule0-42 times -10-6- Joule4-2 times -10-7- Joule4-2 times -10-6- Joule

Question

Toppr Admin · Accepted Answer

In this problem- we have to convert the heat energy in unit from calorie to Joule-xA0-According to work-energy theorem- the work is also a energy-xA0-Thus- 1000k-cal-1000-xD7-103cal-106cal-4-2-xD7-106J -xA0-as 1cal-4-2J-

Work required to produce $1000 k$ - calorie heat will be
$4.2 J o u l e$
$0.42 \times 10^{6} J o u l e$
$4.2 \times 10^{7} J o u l e$
$4.2 \times 10^{6} J o u l e$

In this problem, we have to convert the heat energy in unit from calorie to Joule.
According to work-energy theorem, the work is also a energy.
Thus, $1000 k . c a l = 1000 \times 10^{3} c a l = 10^{6} c a l = 4.2 \times 10^{6} J$ (as $1 c a l = 4.2 J$ )

Work required to produce 1000k - calorie heat will be4.2Joule0.42×106Joule4.2×107Joule4.2×106Joule

In this problem, we have to convert the heat energy in unit from calorie to Joule. According to work-energy theorem, the work is also a energy. Thus, 1000k.cal=1000×103cal=106cal=4.2×106J (as 1cal=4.2J)

Work required to produce $1000 k$ - calorie heat will be
$4.2 J o u l e$
$0.42 \times 10^{6} J o u l e$
$4.2 \times 10^{7} J o u l e$
$4.2 \times 10^{6} J o u l e$

In this problem, we have to convert the heat energy in unit from calorie to Joule.
According to work-energy theorem, the work is also a energy.
Thus, $1000 k . c a l = 1000 \times 10^{3} c a l = 10^{6} c a l = 4.2 \times 10^{6} J$ (as $1 c a l = 4.2 J$ )