Wrap a rubber ball of diameter 12 cm completely with an aluminum foil and the surface smooth- Where will be the image of an object kept 12 cm away from the center of the ball- Is the image real or virtual-

Question

Toppr Admin · Accepted Answer

Surface of a rubber ball is similar to a convex mirror.
Diameter = 12 cm
$$\Rightarrow$$ Radius = 6 cm
2f = R
$$f =\dfrac{R}{2}=\dfrac{6}{2} = 3 cm$$
$$u= \dfrac{12}{2}=6 cm$$
$$v=\dfrac{uf}{u-f}=\dfrac{-6 \times 3}{-6 -3}=\dfrac{-18}{-9}=2cm$$
Mirror is a convex, so image is virtual.

Wrap a rubber ball of diameter 12 cm completely with an aluminum foil and make the surface smooth. Where will be the image of an object kept 12 cm away from the center of the ball? Is the image real or virtual?

Surface of a rubber ball is similar to a convex mirror. Diameter = 12 cm $$\Rightarrow$$ Radius = 6 cm 2f = R $$f =\dfrac{R}{2}=\dfrac{6}{2} = 3 cm$$ $$u= \dfrac{12}{2}=6 cm$$$$v=\dfrac{uf}{u-f}=\dfrac{-6 \times 3}{-6 -3}=\dfrac{-18}{-9}=2cm$$Mirror is a convex, so image is virtual.

Surface of a rubber ball is similar to a convex mirror.
Diameter = 12 cm
$$\Rightarrow$$ Radius = 6 cm
2f = R
$$f =\dfrac{R}{2}=\dfrac{6}{2} = 3 cm$$
$$u= \dfrac{12}{2}=6 cm$$
$$v=\dfrac{uf}{u-f}=\dfrac{-6 \times 3}{-6 -3}=\dfrac{-18}{-9}=2cm$$
Mirror is a convex, so image is virtual.