Write a Pythagorean triplet whose one member is
Pythagorean Triplet is given by (2m,m2−1,m2+1) where m is a positive integer.
(i) 6
Let, 2m=6⇒m=62=3
⇒m2−1=32−1=9−1=8
⇒m2+1=32+1=9+1=10
Therefore, Pythagorean Triplet is (6,8,10)
(ii) 14
Let, 2m=14⇒m=142=7
⇒m2−1=72−1=49−1=48
⇒m2+1=72+1=49+1=50
Therefore, Pythagorean Triplet is (14,48,50)
(iii) 16
Let, 2m=16⇒m=162=8
⇒m2−1=82−1=64−1=63
⇒m2+1=82+1=64+1=65
Therefore, Pythagorean Triplet is (16,63,65)
(iv) 18
Let, 2m=18⇒m=182=9
⇒m2−1=92−1=81−1=80
⇒m2−1=92+1=81+1=82
Therefore, Pythagorean Triplet is (18,80,82)