Write the complement of- -x-5-o -

Question

Write the complement of-  -x-5-o -

Toppr Admin · Accepted Answer

We know that-if two angles are complementary- then their sum is -90-o-Given- the angle is - -x-5-o-Then- the complement of - -x-5-o- is-90-0-x-5-0-90-o-x-5-o-85-o-x-85-x-o-

Write the complement of: $$ (x+5)^o $$.

We know that,
if two angles are complementary, then their sum is $$90^o$$.

Given, the angle is $$ (x+5)^o$$.
Then, the complement of $$ (x+5)^o$$ is:
$$=90^{0}-(x+5)^{0}=90^o-x-5^o=85^o-x=(85-x)^o$$.

Write the complement of: $$ (x+5)^o $$.

We know that,if two angles are complementary, then their sum is $$90^o$$.Given, the angle is $$ (x+5)^o$$.Then, the complement of $$ (x+5)^o$$ is:$$=90^{0}-(x+5)^{0}=90^o-x-5^o=85^o-x=(85-x)^o$$.

We know that,
if two angles are complementary, then their sum is $$90^o$$.

Given, the angle is $$ (x+5)^o$$.
Then, the complement of $$ (x+5)^o$$ is:
$$=90^{0}-(x+5)^{0}=90^o-x-5^o=85^o-x=(85-x)^o$$.