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Question

Write the general term in the expansion of (x2yx)12,x0

Solution
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It is known that the general term Tr+1 which is the (r+1)th term in
the binomial expansion of (a+b)n is given by Tr+1=nCranrbr
Thus, the general term in the expansion of (x2yx)12 is
Tr+1=12Cr(x2)12x(yx)r=(1)r12Cr.x242r.yr.xr=(1)r12Cr.x24r.yr

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