Write the general term in the expansion of (x2−yx)12,x≠0
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Solution
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It is known that the general term Tr+1 which is the (r+1)th term in the binomial expansion of (a+b)n is given by Tr+1=nCran−rbr Thus, the general term in the expansion of (x2−yx)12 is Tr+1=12Cr(x2)12−x(−yx)r=(−1)r12Cr.x24−2r.yr.xr=(−1)r12Cr.x24−r.yr
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