Write the net ionic equation the reaction of potassium dichromate -VI- - K - 2 - Cr - 2 - O - 7 - with sodium sulphite- - Na - 2 - SO - 3 - in an acid solution to give chromium -III- ion and the sulphate ion-

Question

Toppr Admin · Accepted Answer

The equation is-Cr2O2-x2212-7-aq-3SO2-x2212-3-aq-8H-aq-x2192-2Cr3-aq-3SO2-x2212-4-aq-4H2O-liq-

Write the net ionic equation for the reaction of potassium dichromate $(V I)$ , $K_{2} {C r}_{2} O_{7}$ with sodium sulphite, ${N a}_{2} {S O}_{3}$ in an acid solution to give chromium $(I I I)$ ion and the sulphate ion.

The equation is;
$C r_{2} O_{7}^{2 -} (a q) + 3 S O_{3}^{2 -} (a q) + 8 H^{+} (a q) \to 2 C r^{3 +} (a q) + 3 S O_{4}^{2 -} (a q) + 4 H_{2} O (l i q)$

Write the net ionic equation for the reaction of potassium dichromate (VI), K2Cr2O7 with sodium sulphite, Na2SO3 in an acid solution to give chromium (III) ion and the sulphate ion.

The equation is;Cr2O2−7(aq)+3SO2−3(aq)+8H+(aq)→2Cr3+(aq)+3SO2−4(aq)+4H2O(liq)

Write the net ionic equation for the reaction of potassium dichromate $(V I)$ , $K_{2} {C r}_{2} O_{7}$ with sodium sulphite, ${N a}_{2} {S O}_{3}$ in an acid solution to give chromium $(I I I)$ ion and the sulphate ion.

The equation is;
$C r_{2} O_{7}^{2 -} (a q) + 3 S O_{3}^{2 -} (a q) + 8 H^{+} (a q) \to 2 C r^{3 +} (a q) + 3 S O_{4}^{2 -} (a q) + 4 H_{2} O (l i q)$