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Standard IX
Maths
Basic Terms and Definitions
Question
Write the supplement angle of:
$$49^{o}$$
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Solution
Verified by Toppr
The supplement angle of $$49^{o}$$ is,
$$=180^{o}-49^{o}$$
$$=131^{o}$$
Hence, the supplement angle of $$49^{o}$$ is $$131^{o}$$
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