Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

$x = 5, y = 2$ is a solution of the linear equation
$x + 2 y = 7$
$5 x + 2 y = 7$
$x + y = 7$
$5 x + y = 7$

A

5 x + 2 y = 7

B

x + 2 y = 7

C

5 x + y = 7

D

x + y = 7

Open in App

Solution

Verified by Toppr

The solution should satisfy the appropriate equation.
So, let us investigate each option by substituting $x = 5$ & $y = 2$
Option $A$ , $x + 2 y = 7$ .
L.H.S. $= 5 + 2 \times 2 = 9 \neq$ R.H.S.
$∴$ It is not the appropriate equation.
Option $B$ , $5 x + 2 y = 7$
L.H.S. $= 5 \times 5 + 2 \times 2 = 29 \neq$ R.H.S.
$∴$ It is not the appropriate equation.
Option $C$ , $x + y = 7 \Rightarrow$ L.H.S. $= 5 + 2 = 7 =$ R.H.S
$∴$ It is the appropriate equation.
Option $D$ , $5 x + y = 7 \Rightarrow$ L.H.S. $= 5 \times 5 + 2 = 27 \neq$ R.H.S.
$∴$ It is not the appropriate equation.
Hence, option $C$ is correct.

Was this answer helpful?

1

Similar Questions

Q1

x = 5, y = 2 is a solution of the linear equation

(a) x + 2y = 7

(b) 5x + 2y = 7

(c) x + y = 7

(d) 5x + y = 7

View Solution

Q2

x = 5 and y = 2 is a solution of the linear equation ___.

View Solution

Q3

Question 11
x = 5 and y = 2 is a solution of the linear equation:

A) x + 2y = 7
B) 5x +2y = 7
C) x + y = 7
D) 5x + y = 7

View Solution

Q4

If

\frac{2}{x + 2 y} + \frac{1}{x - 2 y} = \frac{- 5}{7}

then prove that

\frac{x}{y} = \frac{2 (10 y - 7)}{(5 x - 21)}

View Solution

Q5

Solve for

x

and

y

:

\frac{y + 7}{5} = \frac{2 y - x}{4} + 3 x - 5

,

\frac{7 - 5 x}{2} + \frac{3 - 4 y}{6} = 5 y - 18

View Solution