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Standard XII
Chemistry
Question
X
e
F
2
reacts with
P
F
5
to give:
X
e
F
6
X
e
F
4
[
P
F
4
]
+
[
X
e
F
3
]
−
[
X
e
F
]
+
[
P
F
6
]
−
A
X
e
F
6
B
[
X
e
F
]
+
[
P
F
6
]
−
C
X
e
F
4
D
[
P
F
4
]
+
[
X
e
F
3
]
−
Open in App
Solution
Verified by Toppr
P
F
5
is a fluoride ion acceptor so it yields cationic species with xenon fluorides.
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6
Similar Questions
Q1
X
e
F
2
reacts with
S
b
F
5
to form:
View Solution
Q2
S
b
F
5
reacts with
X
e
F
4
and
X
e
F
6
to form ionic compounds
[
X
e
F
+
3
]
[
S
b
F
6
−
]
and
[
X
e
F
+
5
]
[
S
b
F
6
−
]
. The geometry of
X
e
F
+
3
,
[
X
e
F
+
5
]
ion respectively is:
View Solution
Q3
X
e
F
2
reacts with
P
F
5
to give:
View Solution
Q4
S
b
F
5
reacts with
X
e
F
4
and
X
e
F
6
to form ionic compounds
[
X
e
F
+
3
]
[
S
b
F
6
]
−
a
n
d
[
X
e
F
+
5
]
[
S
b
F
−
6
]
.
The geometry of
X
e
F
+
3
ion and
X
e
F
+
5
ion, respectively, is :
View Solution
Q5
What is the product formed when
X
e
F
4
reacts with
S
b
F
5
?
View Solution