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Question

XY2 dissociates as:

XY2(g)XY(g)+Y(g)

When the initial pressure of XY2 is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction assuming that the volume of the system remains unchanged.

  1. 50
  2. 166.6
  3. 100
  4. 400

A
50
B
166.6
C
100
D
400
Solution
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XY2(g)XY(g)+Y(g)

The initial pressure of XY2 is 600 mm Hg.

Let x mm Hg be the change in pressure of XY2 to reach equilibrium.

The equilibrium pressures of XY2, XY and Y are (600x) mm Hg, x mm Hg and x mm Hg respectively.

Total pressure at equilibrium =(600x)+x+x=600+x mm Hg. But it is equal to 800 mm Hg.

(600+x)=800

x=200 mm Hg

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