Y- e - -3x - Prove -dfrac - - d - 2 -y - - dx - 2 - - -dfrac - dy - dx - -6y-0

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$y = e^{- 3 x}$ . $P r o v e : \frac{d^{2} y}{{d x}^{2}} + \frac{d y}{d x} - 6 y = 0$

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