You are given many resistances- capacitors and inductors- These are connected to a variable DC voltage -the first two circuits- or an AC voltage of 50 Hz frequency -the next three circuits- in different ways as shown in List 2- When a current I -steady state DC or rms AC- flows through the circuit- the corresponding voltage V-1- and V-1- -indicated in circuits- are related as shown in List 1-Match the two

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Toppr Admin · Accepted Answer

XL- 2-x3C0-50-6-xD7-10-x2212-3- -6-x3C0-xD7-10-x2212-1XC - 12-x3C0-50-xD7-3-xD7-10-x2212-6 - 1043-x3C0-XC-gt-XL

i.	$I \neq 0, V_{1}$ is proportional to $I$	a.
ii.	$I \neq 0, V_{2} > V_{1}$	b.
iii.	$V_{1} = 0, V_{2} = V$	c.
iv.	$I \neq 0, V_{2}$ is proportional to $I$	d.
		e.

i	$I \neq 0, V_{1} is proportional to I$	a
ii	$I \neq 0, V_{2} > V_{1}$	b
iii	$V_{1} = 0, V_{2} = V$	c
iv	$I \neq 0, V_{2} is proportional to I$	d
		e

i.	$I \neq 0, V_{1}$ is proportional to $I$	a.
ii.	$I \neq 0, V_{2} > V_{1}$	b.
iii.	$V_{1} = 0, V_{2} = V$	c.
iv.	$I \neq 0, V_{2}$ is proportional to $I$	d.
		e.

XL= 2π(50)(6×10−3) =6π×10−1XC = 12π(50)×3×10−6 = 1043πXC>XL

$X_{L}$ = $2 π (50) (6 \times 10^{- 3})$ = $6 π \times 10^{- 1}$
$X_{C}$ = $\frac{1}{2 π (50) \times 3 \times 10^{- 6}}$ = $\frac{10^{4}}{3 π}$
$X_{C} > X_{L}$