Zeroes the end of 125-

Question

Toppr Admin · Accepted Answer

Zeros at the end of 125-x21D2-x-x5-x52- is the box function-x21D2-125-1255-12552-12553-12554-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -25-5-1-0-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -31 zerosHence- the answer is 31-

Zeroes at the end of $125!$

Zeros at the end of $125!$
$\Rightarrow x! = [\frac{x}{5}] + [\frac{x}{5^{2}}] + . . . . . .$
$[.]$ is the box function
$\Rightarrow 125! = [\frac{125}{5}] + [\frac{125}{5^{2}}] + [\frac{125}{5^{3}}] + [\frac{125}{5^{4}}]$
$= 25 + 5 + 1 + 0.....$
$= 31$ zeros
Hence, the answer is $31.$

Zeroes at the end of 125!

Zeros at the end of 125!⇒x!=[x5]+[x52]+......[.] is the box function⇒125!=[1255]+[12552]+[12553]+[12554] =25+5+1+0..... =31 zerosHence, the answer is 31.

Zeroes at the end of $125!$

Zeros at the end of $125!$
$\Rightarrow x! = [\frac{x}{5}] + [\frac{x}{5^{2}}] + . . . . . .$
$[.]$ is the box function
$\Rightarrow 125! = [\frac{125}{5}] + [\frac{125}{5^{2}}] + [\frac{125}{5^{3}}] + [\frac{125}{5^{4}}]$
$= 25 + 5 + 1 + 0.....$
$= 31$ zeros
Hence, the answer is $31.$