Triangles

Maths

Class 9

$(a+b)x+(a−b)y−2ab=0.......(1)$

$(a−b)x+(a+b)y−2ab=0.......(2)$

and $x+y=0......(3)$ form an isosceles triangle whose vertical angle is $2tan_{−1}(a/b)$.

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In an isosceles triangle any two angles of a triangle are same .

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Hence, $∠BAC=∠ACD$.

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