Quadratic Equations

Quadratic Equation Practice Problem 1

The roots of the quadratic equation ( a + b -2c )x² – ( 2a – b – c)x +( a – 2b + c) = 0 are-

A. (a + b + c ) and (a – b- c)

B.  \( \frac{1}{2} \) and a – 2b + c

C. a – 2b + c and  \( \frac{1}{(a + b – 2c)} \)

D. None of the above.

Answer

Clearly we see that x=1 satisfies the equation

⇒x=1 is a root of the that equation

Let α be other root

Product of roots =1 × α =  \( \frac{a – 2b + c}{a + b – 2c} \)

other root =  α = \( \frac{a – 2b + c}{a + b – 2c} \)

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