 # Python hex()

The python hex function is used to convert an integer to is an equivalent hexadecimal string

The syntax of the python hex function is as follows:

hex(x) Source Code

### hex() Parameter

The python hex function takes one argument as the input from the user.

x- is an integer. The argument is either an int object or it has to define an _index_() method that gives you an integer

### Return Value from hex()

The python hexadecimal function returns a hexadecimal string with the 0x format.

Here’s is an example for the same:

Source Code:

                    
print("10 in hexadecimal is: ", hex(10))

val = hex(100) # returns string type

print(type(val))

Output

<class 'str'>




To convert a floating-point number to a hexadecimal number, users can use the float.hex().

Source Code:

                    
print("The equivalent value of the hexadecimal 3.9 is: ", float.hex(10.1)) # valid

Output:

0x1.4333333333333p+3



Errors:

In case of any errors, the TypeError exception is returned.

What does hex do in Python?

The hex() in python is used to return a number in the hexadecimal format.

Here are some examples of the python hex().

Example 1: How hex() works?

                    
number = 435

print(number, 'in hex =', hex(number))

number = 0

print(number, 'in hex =', hex(number))

number = -34

print(number, 'in hex =', hex(number))

returnType = type(hex(number))

print('Return type from hex() is', returnType)

Output

435 in hex = 0x1b3

0 in hex = 0x0

-34 in hex = -0x22

Return type from hex() is <class 'str'>




Example 2: Hexadecimal representation of a float

                    
number = 2.5

print(number, 'in hex =', float.hex(number))

number = 0.0

print(number, 'in hex =', float.hex(number))

number = 10.5

print(number, 'in hex =', float.hex(number))

Output

2.5 in hex = 0x1.4000000000000p+1

0.0 in hex = 0x0.0p+0

10.5 in hex = 0x1.5000000000000p+3




How do you write hex in python?

To derive a hexadecimal number, the hex() is used. The given number is converted to a hexadecimal value using this function.

Program to convert the decimal value to a hexadecimal form

Source Code:

                    
numb1 = int(input("enter base 10 no\n"))

print("b. Decimal to Octal")

print("c. Decimal to Binary")

choice = input()

if choice is 'a':

print("the number in hexadecimal is" + str(number) +

" is " + hex(number).lstrip("0x").rstrip("L"))

if choice is 'b':

print("the number in octal" + str(number) +

" is " + oct(number).lstrip("0o").rstrip("L"))

if choice is 'c':

print("the number i binary" + str(number) +

" is "+bin(number).lstrip("0b").rstrip("L"))

Output :

input variant a)

enter base 10 no

123

Decimal to Octal
Decimal to Binary

a

The number in hexadecimal is 123 is 7b




How do you find the hex value in Python?

The hex() function is a built-in Python function for converting an integer value to its hexadecimal equivalent. Look at some examples below to understand the working of the hex():

Example 1:

                    
print("The hexadecimal form of 23 is "

+ hex(23))

print(" 'a' in hexadecimal is" + hex(ord('a')))

print("The hexadecimal form of 3.9 is "

+ float.hex(3.9))

Output :

The hexadecimal form of 23 is 0x17

The hexadecimal form of 3.9 is 0x1.f333333333333p+1




Example 2: The TypeError function is raised when any other datatype rather than an integer is passed as the argument.

Source Code:

                    
print("11.1 hexadecimal format is "

+ hex(11.1))
Output :

Traceback (most recent call last):

File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in

The 'float' object cannot be read as an integer, which causes a TypeError.





How do you decipher hex to text in Python?

To convert hexadecimal in python to text, the user will have to implement the bytes.fromhex() AND bytes.decode(). To construct a bytes object, use bytes.fromhex(string) with a hexadecimal string without “0x” at the beginning as a string. To convert this byte object to an ASCII version of the original hexadecimal string, call bytes.decode(encoding) using “ASCII” as encoding.

Source Code

                    
# Remove the leading 0x from the string by slicing it.

hex_string = "0x616263"[2:]

bytes_object = bytes.fromhex(hex_string)

Convert to bytes object

ascii_string = bytes_object.decode("ASCII")

Convert to ASCII representation

print(ascii_string)

OUTPUT

abc



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