A circle is a closed figure that can be drawn using a constant length from a fixed-point center. A sphere is a three-dimensional circle. Circle and sphere both are round and measured using radius. Here we are going to calculate the surface area, the volume of a sphere by different sphere formula.
Sphere Formula
What is the Sphere?
A sphere is a three-dimensional counterpart of a circle, with all its points lying in space at a constant distance from the fixed point or the center, called the radius of the sphere. Radius of the sphere denoted as r.
The diameter of a sphere: The line passing through the center from one end to the other called the diameter of the sphere. The diameter of the sphere denoted as D.
Diameter = 2 times radius of the sphere
D = 2 × r
Circumference of a sphere: Circumference of a sphere is the distance covered around the sphere. The unit of the circumference is the same as the radius.
Circumference = \(2 \times \pi \times r\)
The surface area of a sphere: The surface area of a sphere is the number of square units that will exactly cover the surface of a sphere. The unit of the surface area of sphere is a square unit m²
The surface area of a sphere is
Surface Area of sphere = 4 times the area of a circle
Surface Area of sphere =\(4 \times \pi \times r^{2}\)
Where
 r | the radius of the sphere |
The volume of a sphere: Volume of sphere is the number of cubic units that fill a sphere. The unit of volume of the sphere is a cubic unit m³
The volume enclosed by a sphere is
Volume of sphere = \(\frac{4}{3}\)π r³
Where,
 r | the radius of the sphere |
The volume of spherical shell: A spherical shell is a region between two concentric spheres having different radii.
Volume of a spherical shell = \(\frac{4}{3}\pi R^{3} – \frac{4}{3}\pi r^{3}\)
V =\(\frac{4}{3}\pi (R^{3}-r^{3})\)
Where,
R | The outer radius of the sphere |
r | The inner radius of the sphere |
Solved Examples
Q 1:Â The radius of the sphere is 5 cm. Find the diameter, circumference, surface area and volume of a sphere?
Solution: Given, r = 5 cm
Diameter of a sphere = 2 × r
= 2 × 5
=10 cm
Circumference of a sphere = \(2\times \pi \times r\)
= \(2\times \pi \times 5\)
= 31.41 cm
Surface Area of sphere =\(4 \times \pi \times r^{2}\)
= \(4 \times \pi \times 5^{2}\)
= \(4 \times \times 3.14 Â \times 25\)
= 314.16 cm²
Volume of a sphere = \(\frac{4}{3}\pi r^{3}\)
= \(\frac{4}{3}\pi 5^{3}\)
= \(\frac{4}{3} \times 3.14 \times 125\)
= 523.60 cm³
Q 2: A shopkeeper has one ladoo of radius 10 cm. With the same material used to form a big ladoo, how many ladoos of radius 5 cm can be made.
Solution: Let the number of smaller ladoos that can be made from a bigger ladoo be x.
Here,
The radius of the bigger ladoo (R) = 10 cm
The radius of the smaller ladoo (r) = 5 cm
So, the volume of the big ladoo is equal to the volume of x small ladoos.
Volume of the big ladoo = Volume of the x small ladoos
\(\frac{4}{3}\pi R^{3}\) = \(\frac{4}{3}\pi r^{3}\)
\(\frac{4}{3}\pi 10^{3}\) = \(x\frac{4}{3}\pi 5^{3}\)
\(10^{3} = x 5^{3}\)
x = \(\frac{10^{3}}{5^{3}}\)
x = \(\frac{1000}{125}\)
x = 8
Therefore, 8 ladoos of 5 cm can be made from one big ladoo of radius 10 cm.
I get a different answer for first example.
I got Q1 as 20.5
median 23 and
Q3 26