Chemistry Formulas

Charles Law Formula

Charles law is an experimental gas law. It explains how gases tend to expand when heated. French physicist Charles studied the effect of temperature on the quantity of a gas at constant pressure. This law describes how a gas expands because of the temperature increases; conversely, a decrease in temperature will cause a decrease in volume. During this article, we’ll discuss Charles law formula, its properties and therefore the experiment performed for verification.

Charles Law Formula

Definition of Charles Law Formula is, “When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and therefore the volume is going to be in direct proportion.”

The equation of the law is PV = k.

  • k may be a constant.
  • P= Pressure
  • V= Volume

Therefore, V=kT. For comparing an equivalent substance under two different sets of conditions, the law is often written as

\( \frac {Vi}{Vf} = \frac {Ti}{Tf} \)

  • Vi = First Volume
  • Vf= Second Volume
  • Ti= First Temperature
  • Tf = Second Temperature

The equation shows that, as temperature increases, the quantity of the gas also increases in proportion.

Charles’s law appears to imply that the quantity of gas will descend to zero at a particular temperature (−266.66 °C consistent with Gay-Lussac’s figures) or −273.15 °C. At temperature, the gas is having zero energy and hence the molecules restrict motion. Charles from his experiments concluded that at constant pressure, the quantity of a hard and fast amount of a gas increases or decreases by 1⁄273 (now 1⁄273.15) times the quantity at 0 °C for each 1 °C rise or fall in temperature.

Experiment Verification of Charles law

We can verify Charles’ law experimentally and determine the value of temperature with regard to the above figure. the first apparatus of the experiment consists of a conical flask and a beaker. The empty flask is submerged into the water-filled beaker as shown within the above diagram. When the warmth is supply to the beaker by a burner, it also heats the air within the flask.

Charles Law Formula

Source: chemistrygod.com

As a consequence, the air inside the flask expands. this is often our condition 1. The flask is later dipped during a cistern at temperature. Now, the air within the flask contracts since the temperature is decreased. this is often condition 2. By knowing the temperature and volume of both conditions, we will verify the law.

Limitations of Charles law

Charles’s law is applicable to only ideal gases. Charles law holds good for real gases only at high temperatures and low pressures. the connection between the quantity and temperature isn’t linear in nature at high pressures.

Solved Examples for Charles Law Formula

Q 1] Find the initial volume of a gas at 300 K, if the ultimate volume is 6 L at 200 K

Solution: Given, V2 =6 L T1= 300 K T2= 200 K

V1=?

Using Charles Law,

(V1)(T1)=(V2)(T2)

(V1)(300)=(6)(200)

V1= 3 L

The initial volume of a gas at 300 K is 3 litres.

Q 2] A gas occupies a volume of 300cm3 at 0°C(degree celsius) and 780 torrs. What volume (in liters) will it occupy at 80°C (degree celsius) and 780 mm Hg?

Solution: Given,

  • V1= 300 cm³
  • T1= 0° C = 0+273 = 273 K
  • T2= 80° C = 80+273 = 353 K
  • V2 =?

Here the pressure is constant and only the temperature is modified.

Using Charles Law,

(V1)(T1)=(V2)(T2)

300 * 273=V2 *353

V2=232.011cm3

1 milliliter = 0.001 litre =1 x 10-3 litre

∴ 232.011cubic centimeter = 232.011 x 10-3 = 0.232 litres

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