CALCULATE ELECTIC FEILD INTENSITY DUE TO DATIPOLE OF LENTH 10 CM HAVING CHARGE 5000MICROCOULUMB AT POINT ON AXIS OF LENTH 20 CM FROM ONE OF THE CHARGE

### Asked by CHITTIBOMMAPARDHANADH | 6th Sep, 2021, 02:27: PM

Expert Answer:

###
Figure shows the dipole having charge 500 μC separated by a distance 10 cm .
Electric field at a point P which is at a distance 20 cm from charge at B is given by
where K = 1/(4πε_{o} ) = 9 × 10^{9} N m^{2} C^{-2} is Coulomb's constant ^{ }, q = 500 μC is magnitude of
each charge of dipole , d_{A }= 0.2 m is the distance from positive charge to the point P
and d_{B} = 0.3 m is the distance from negative charge to point P .

_{o}) = 9 × 10

^{9}N m

^{2}C

^{-2}is Coulomb's constant

^{ }, q = 500 μC is magnitude of

_{A }= 0.2 m is the distance from positive charge to the point P

_{B}= 0.3 m is the distance from negative charge to point P .

### Answered by Thiyagarajan K | 6th Sep, 2021, 03:40: PM

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