In a basket, there are 6 grapes, 11 bananas and 13 oranges. If one fruit is chosen at random. What is the probability that the fruit is either a grape or a banana
- A.^{6}/_{30}
- B.^{5}/_{30}
- C.^{17}/_{30}
- D.^{11}/_{30}
Correct Answer: Option C
Explanation
Number of grapes = 6
Number of banana = 11
Number of oranges = 13
Total = 30
P(Grape) = ^{6}/_{30}, P(Banana) = ^{11}/_{30}
P(Orange) = ^{13}/_{30}
∴P(Either grape or banana) = ^{6}/_{30} + ^{11}/_{30}
= ^{17}/_{30}