Geometric Series form a very important section of the IBPS PO, SO, SBI Clerk and SO exams. A geometric series is also known as the geometric progression. It is a series formed by multiplying the first term by a number to get the second term, this process is continued until we get a number series in which each number is some multiple of the previous term. Such a progression increases swiftly and thus has the name geometric progression.

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## Geometric Series or Geometric Progression

Geometric Progression or a G.P. is formed by multiplying each number or member of a series by the same number. This number is called the constant ratio. In a G.P. the ratio of any two consecutive numbers is the same number that we call the constant ratio. It is usually denoted by the letter ‘r’. Thus if we have a G.P. say a1, a2, a3, …, a_{n}, the ratio of any two consecutive numbers within the series will be same. Therefore for the series present above, we shall have:

a3/a2 = r; where ‘r’ is the common ratio. In other words, if you know ‘r’ and the first term, you can generate the entire Geometric Progression.

**Browse more Topics Under Number Series**

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- Simplification on BODMAS Rule
- Chain Rule
- Heights & Distances
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- Number Series Practice Questions

Example 1: In a G.P., r = 2 and a = 1. Then the tenth term of the G.P. will be?

A) 16Â Â Â Â Â Â B) 19Â Â Â Â Â Â C) 26Â Â Â Â D) 512

Answer: In a G.P. as we saw, each term is multiplied by the common ration ‘r’. To get the second term, the first term is multiplied by ‘r’. We get the third term by multiplying the first term by ‘r^{2}‘. Similarly, we will get the fourth term by multiplying the first term by r^{3} and so on. Knowing this the above example becomes very easy. Since the first term is 1, we have to multiply it by 2^{9} to get the tenth term = 512. So the tenth term of the G.P. = 512. The correct option thus is D) 512.

### Sum of the Geometric Progression

Sometimes you will be given the series and asked to find the sum of the first few terms or the entire series. The sum is denoted by S_{n}; where ‘n’ is the number of the term up to which the sum is being found out. For example, the sum of the first ten terms will be denoted by S_{10}. Here we will list important formulae to find out the sum of the first few terms. Let ‘a’ be the first term of a G.P. and ‘r’ be the common ratio, then the sum of the G.P. can be found out by the following formulae:

_{SnÂ }= a (r^{nÂ }-1)/ r-1,Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â if r â‰ 1 Â and

S_{nÂ }= anÂ ,Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â if r = 1

Sum of infinite terms Â of a G.P. in case of Â -1 < r <1 is given by the following formula:

_{Sn}= a/(1-r).

So there are three formulae depending on the value of ‘r’. We will see examples of each below.

## Formula One S_{nÂ }= a (r^{nÂ }-1)/ (r-1)

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This formula is only valid when r â‰ 1. For example, consider the following series.

Example 2: Find the sum of the first 5 terms of the following series. Given that the series is finite: 3, 6, 12, …

A) 92Â Â Â Â Â Â B) 24Â Â Â Â Â C) 93/4Â Â Â Â Â D) 27

Answer: The first step is to confirm that the series is actually a G.P. You can verify it by dividing the consecutive terms. Remember divide two sets of consecutive terms. For example, in the above example, 6/3 = 2 and 12/6 = 2. Hence the series is a G.P. with a common ratio or r = 2. Also, we see that a = 3, thus we can use the first formula and find the sum of any number of terms of such series.

To find the sum of the first 5 terms, we note that n = 5, a = 3, and r = 2. Thus we have:

S_{5} = 3(2^{5} – 1)/(5 -1) = 93/4

Thus the option is C)Â 93/4.

## Second And Third Formulae For The Sum

The second formula works only when r = 1. this is pretty straightforward. In this case, each term of the G.P. will be same. The following trick question may be asked from this concept.

Q 1: What type of series is the following sequence of ‘n’ numbers:

1, 1, 1, 1, 1, 1, 1, ….., 1

B) Simple Series

C) Mixed Series

D) Geometric Progression

Answer: The above series is clearly a Geometric Progression with the first term = 1 and the common ratio or r = 1 also. The sum of ‘n’ terms will be n(1) = n. Therefore, the correct option is D) Geometric Series.

The third formula is only applicable when the number of terms in the G.P. is infinite or in other words, the series doesn’t end anywhere. Also, the value of r should be between -1 and 1 but not equal to any of the two. -1 < r <1.

## Practice Questions

Q 1: In a Geometric Progression, the first term a = 10. The ratio of two consecutive terms is 2. What will be the sixth term of the series?

A) 320Â Â Â Â Â B) 640Â Â Â Â Â Â C) 300Â Â Â Â Â D) 298

Ans: A) 320.

Q 2: Find the sum of the first five terms of the G.P.: 5, 25, 125, 625,… The G.P. has a thousand terms in it.

A) 395Â Â Â Â Â B) 3905Â Â Â Â Â C) 935Â Â Â Â Â D) 9305

Ans: B) 3905

5 7 31 283 ?

5Ã—1+2=7

7Ã—4+3=31

31Ã—9+4=283

283Ã—16+5=4533

4,8,24,28,84,88,_

84+100=184or 84+240=324

1 5 20 ???

1Ã—2+3=5Ã—3+5=20Ã—4+7=86

16,4,68,12,?,4,30,1,9 plz reply i need it

GAY

2,3,3,5,10,13,?,43,172,177

4,5,5,7,9,13,10__,14

I think

Answer. 15

In series of odd numbers (4, 5,9,10,14) there is addition of 1 and 4 alternately.

And in series of even numbers (5, 7,13,?) There is addition of 2 and 6 alternately.

Find missing teams-1,5,14,?,44

Find the missing number of this series

60,50,60,90,41,_?

Options 1. 12

2. 18

3. 25

4. 30

5. none this above

26,4,20,10,14,16,8,22,2,28

____,360,000,000,____, 389,000,000,____, 420,000,000

37 52 93 75 29 ? what is the math behind this

2,1,0,-3,-24,? Find the next number

Upper line 3 5 8 mid line 6 10 32 lower line 9 ? 50 me missing no. Kya h

94 101 115 136 164 ?

199

QID : 426 – In the following question, select the

missing number from the given alternatives.

41, 83, 167, 335, 671, ?

Options:

1) 1297

2) 1343

3) 1447

4) 1661

1343

50,50,54,72,?,220