> > Componendo-Dividendo

# Componendo-Dividendo

Componendo-Dividendo or componendo and dividendo is a rule that we use to compare and study ratios and proportions. In the following section, we will state this rule and also see some examples that will help us use this method to solve the questions from this section. Let us see.

### Suggested Videos

Area of Triangles
Coin Toss
VST Permutations and Combinations Problem 1 and its Solution

## Componendo-Dividendo

Componendo and dividendo is a theorem on proportions that allows for a quick way to perform calculations and reduce the number of expansions needed. It is particularly useful when dealing with equations involving fractions or rational functions in mathematical Olympiads, especially when you see fractions.

Hence, if the ratio of any two numbers is equal to the ratio of another two numbers, then the ratios of the sum of numerator and denominator to the difference of numerator and denominator of both rational numbers are equal. First, let us start by defining some important terms. Let us see:

### Direct Proportion

Two quantities are said to be directly proportional, if on the increase (or decrease) of the one, the other increases (or decreases) to the same extent.

Example 1:Â Cost is directly proportional to the number of articles. (More Articles, More Cost)
Example 2: Work done is directly proportional to the number of men work (More Men, More Work).

### Indirect Proportion

Two quantities are said to be indirectly proportional if on the increase of the one, the other decreases to the same extent and vice-versa.

Example 1:Â The time taken by a car is covering a certain distance is inversely proportional to the speed of the car. (More speed, Less is the time taken to cover a distance.)

Example 2: The time taken to finish a work is inversely proportional to the number of persons working at it. (More persons, Less is the time taken to finish a job).
Remarks: In solving problems by the chain rule, we compare every item with the term to be found out.

### Key Points

If p : q :: r : s, then:

The method of finding the 4 th term of a proportion when three are given is known as the rule of three as above. Three or more quantities are said to be in compound proportion if one quantity depends on the other remaining quantities. If p,q,r,s are four quantities & if p : q :: r : s then:

### Componendo

(p+q)/q = (r+s)/s

### Dividendo

(p-q)/p = (r-s)/s

### Componendo & Dividendo

(p+q)/(p-q) = (r+s)/(r-s)

q/p = s/r

p/r = q/s

## Solved Examples For You

### Part I

Example 3: Prove the componendo and dividendo formula.

Answer: Let a, b, c and d be four quantities such that, a : b = c : d

In other words, we may write a/b = c/d

We can write b/a = d/c [By invertendo]

(a+b)/b = (c+d)/dÂ  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  [By componendo].

Thus we have, (a-b)/b = (c-d)/dÂ  Â  Â  Â  Â  Â  Â  Â  Â  [By dividendo]

Hence, we can write (a+b)/(a-b) = (c+d)/(c-d)Â  Â  Â  Â  Â  Â  Â  Â  [On dividing (i) by (ii)]

In other words we may write, (a+b):(a-b) = (c+d):(c-d).

Hence we can write a:b = c:d and (a+b):(a-b) = (c+d):(c-d).Â Therefore, it is proved that if the ratio of a to b is equal to the ratio of c to d, then the ratio of a + b toÂ a âˆ’ b is equal to the ratio of cÂ + dÂ toÂ c âˆ’ d. This property is called the componendo and dividendo rule.

Example 4: If p = 4xy/(x+y), then the value of (p+2x)/(p-2x) + (p+2x)/(p-2y) will be:

A) px – xyÂ  Â  Â  Â  Â  Â  Â  B) P(x+y)Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â C) xypÂ  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â D) 2

Answer: Here we have: p = 4xy/(x+y) which will imply that p/2x = 2y/(x+y). In other words we can say that:

(p+2x)/(p-2x) = (2y + x + y)/(2y – (x + y))Â  Â  Â  Â  Â  Â  Â  [By componendo and dividendo]

(p +Â  2x)/(p-2x) = (3y + x)/(y – x)Â  Â  Â  Â  Â  Â  ….. (i)

Again, we can say that p = 4xy/(x+y)Â  Â  and we can say that p/2y = 2x/(x + y)

Also, this means thta (p + 2y)/(p – 2y) = (2x + x + y)/(2x – (x +y))Â  Â  Â  Â  Â  [By componendo and dividendo]

Therefore, we have: (p + 2y)/(p – 2y) = (3x + y)/(x – y) ….(ii)

Adding (i) and (ii), we get:

(p + 2x)/(p – 2x) + (p + 2y)/(p – 2y) = (3y + x)/(y – x) + (3x + y)/(x – y)

In other words, this can be written as: (3y + x)/(y -x) – (3x + y)/(y – x) = (3y + x – 3x – y)/(y -x) = (2y – 2x)/(y – x)

Hence, we have: 2(y – x)/(y – x) = 2. Hence the correct option here isÂ D) 2.

### Part II

Let us see a few more examples to get ourselves well acquainted with the concept of componendo and dividendo.

Example 5: If (4a + 9b) x (4c â€“ 9d) = (4a â€“ 9b) (4c + 9d), then the value of a:b can be equal to:

A) c:dÂ  Â  Â  Â  Â  Â  Â  Â  Â B) 2Â  Â  Â  Â  Â  Â  Â  Â  Â  C) ab:cÂ  Â  Â  Â  Â  Â  Â  Â  Â  Â D) bc:a

Answer: Here we have: (4a + 9b) x (4c â€“ 9d) = (4a â€“ 9b) (4c + 9d). In other words we can say that: (4a + 9b)/(4a – 9b) = (4c + 9d)/(4c – 9d)

Hence we have: {(4a + 9b) + (4a – 9b)}/{(4a + 9b) – (4a – 9b)} = {(4c + 9d) + (4c – 9d)}/{(4c + 9d) – (4c – 9d)}Â  Â  Â  Â  Â  Â  [By componendo and dividendo]

In other words we have: 8a/18b = 8c/18d.

Or we may write: a/b = c/d i.e. a:b :: c : d.

Hence a:b = c: d and the correct option here isÂ A) c:d. Let us see another example below.

## Practice Question:

Q 1: If (x : y) = 2 : 1, then (x2 – y2) : (x2 + y2) is:

A) 3: 5Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  B) 5 : 3Â  Â  Â  Â  Â  Â  Â  Â  Â  Â C) 1:3Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â D) 3:1

Ans:Â A) 3: 5

Share with friends

## Customize your course in 30 seconds

##### Which class are you in?
5th
6th
7th
8th
9th
10th
11th
12th
Get ready for all-new Live Classes!
Now learn Live with India's best teachers. Join courses with the best schedule and enjoy fun and interactive classes.
Ashhar Firdausi
IIT Roorkee
Biology
Dr. Nazma Shaik
VTU
Chemistry
Gaurav Tiwari
APJAKTU
Physics
Get Started

## Browse

##### Ratios and Proportions

0 Followers

Most reacted comment
1 Comment authors
Recent comment authors
Subscribe
Notify of
Guest
hope

could someone please explain the following questions and answers 1. Raju and Sanjay had 35% and 45% rupees more than Ajay respectively. What is the ratio of Raju and Sanjayâ€™s money? A. 7:9 B. 27:29 C. 37:39 D. 27:39 The correct answer is C. 2. Two men earn a yearly salary in the ratio 10:13. If there spending is in the ratio of 4:5 and the man spending lesser of the two saves Rs. 6000 while the other one saves Rs. 8000, then find the salary of the person who is higher paid. A. Rs. 12000 B. Rs. 14000 C.… Read more »

Guest
yyyyy

## Question Mark?

Have a doubt at 3 am? Our experts are available 24x7. Connect with a tutor instantly and get your concepts cleared in less than 3 steps.

No thanks.